3867. Sum of GCD of Formed Pairs
You are given an integer array nums of length n.
Construct an array prefixGcd where for each index i:
- Let
mxi = max(nums[0], nums[1], ..., nums[i]). prefixGcd[i] = gcd(nums[i], mxi).
After constructing prefixGcd:
- Sort
prefixGcdin non-decreasing order. - Form pairs by taking the smallest unpaired element and the largest unpaired element.
- Repeat this process until no more pairs can be formed.
- For each formed pair, compute the
gcdof the two elements. - If
nis odd, the middle element in theprefixGcdarray remains unpaired and should be ignored.
Return an integer denoting the sum of the GCD values of all formed pairs.
The termgcd(a, b) denotes the greatest common divisor of a and b.
Example 1:
Input: nums = [2,6,4]
Output: 2
Explanation:
Construct prefixGcd:
i |
nums[i] |
mxi |
prefixGcd[i] |
|---|---|---|---|
| 0 | 2 | 2 | 2 |
| 1 | 6 | 6 | 6 |
| 2 | 4 | 6 | 2 |
prefixGcd = [2, 6, 2]. After sorting, it forms [2, 2, 6].
Pair the smallest and largest elements: gcd(2, 6) = 2. The remaining middle element 2 is ignored. Thus, the sum is 2.
Example 2:
Input: nums = [3,6,2,8]
Output: 5
Explanation:
Construct prefixGcd:
i |
nums[i] |
mxi |
prefixGcd[i] |
|---|---|---|---|
| 0 | 3 | 3 | 3 |
| 1 | 6 | 6 | 6 |
| 2 | 2 | 6 | 2 |
| 3 | 8 | 8 | 8 |
prefixGcd = [3, 6, 2, 8]. After sorting, it forms [2, 3, 6, 8].
Form pairs: gcd(2, 8) = 2 and gcd(3, 6) = 3. Thus, the sum is 2 + 3 = 5.
Constraints:
1 <= n == nums.length <= 1051 <= nums[i] <= 109
ArrayMathTwo PointersSortingSimulationNumber Theory
Hints
Hint 1
Maintain a running prefix maximum
mxi while iterating nums to compute prefixGcd[i] = gcd(nums[i], mxi).Hint 2
Sort
prefixGcd in non-decreasing order.Hint 3
Form pairs by combining smallest unpaired and largest unpaired elements.
Hint 4
Compute gcd for each pair and sum them; ignore middle element if
n is odd.Preparing judge…