3957. Maximum Sum of M Non-Overlapping Subarrays II
You are given an integer array nums of length n, and three integers m, l, and r.
Your task is to select at least one and at most m non-overlapping subarrays from nums such that:
- Each selected subarray has a length between
[l, r](inclusive). - The total sum of all selected subarrays is maximized.
Return the maximum total sum you can achieve.
Example 1:
Input: nums = [4,1,-5,2], m = 2, l = 1, r = 3
Output: 7
Explanation:
One optimal strategy is to:
- Select the subarray
[4, 1]with sum4 + 1 = 5and the subarray[2]with sum 2. Both subarrays have length between[l, r]. - The total sum of these subarrays is
5 + 2 = 7, which is the maximum achievable sum with at mostm = 2subarrays.
Example 2:
Input: nums = [1,0,3,4], m = 2, l = 1, r = 2
Output: 8
Explanation:
One optimal strategy is to:
- Select the subarray
[1]with sum1and the subarray[3, 4]with sum3 + 4 = 7. Both subarrays have length between[l, r]. - The total sum of these subarrays is
1 + 7 = 8, which is the maximum achievable sum with at mostm = 2subarrays.
Example 3:
Input: nums = [-1,7,-4], m = 1, l = 2, r = 3
Output: 6
Explanation:
- Select the subarray
[-1, 7]fromnumswhich has length between[l, r]. - The total sum of this subarray is
-1 + 7 = 6, which is the maximum achievable sum with at mostm = 1subarray.
Example 4:
Input: nums = [-3,-4,-1], m = 2, l = 1, r = 2
Output: -1
Explanation:
- All subarrays of
numshave negative sums. The optimal strategy is to select the subarray[-1], which has length between[l, r]. - The total sum of this subarray is -1, which is the maximum achievable sum with at most
m = 2subarrays.
Constraints:
1 <= n == nums.length <= 105-105 <= nums[i] <= 1051 <= m <= n1 <= l <= r <= n
ArrayBinary SearchDynamic ProgrammingQueueSliding WindowPrefix SumMonotonic Queue
Hints
Hint 1
WQS Binary Search
Hint 2
Instead of directly limiting the number of selected subarrays, assign a penalty
x for choosing each subarray.Hint 3
For a fixed penalty
x, maximize the adjusted value sum - x * count, while also tracking how many subarrays are chosen.Hint 4
For each fixed penalty, use a deque to optimize transitions over previous split points whose distance is between
l and r.Hint 5
As
x increases, the optimal number of selected subarrays decreases, so binary search the penalty.Hint 6
Convert the adjusted answer back by adding
x * m.Preparing judge…