2600. K Items With the Maximum Sum
There is a bag that consists of items, each item has a number 1, 0, or -1 written on it.
You are given four non-negative integers numOnes, numZeros, numNegOnes, and k.
The bag initially contains:
numOnesitems with1s written on them.numZeroesitems with0s written on them.numNegOnesitems with-1s written on them.
We want to pick exactly k items among the available items. Return the maximum possible sum of numbers written on the items.
Example 1:
Input: numOnes = 3, numZeros = 2, numNegOnes = 0, k = 2
Output: 2
Explanation: We have a bag of items with numbers written on them {1, 1, 1, 0, 0}. We take 2 items with 1 written on them and get a sum in a total of 2.
It can be proven that 2 is the maximum possible sum.
Example 2:
Input: numOnes = 3, numZeros = 2, numNegOnes = 0, k = 4
Output: 3
Explanation: We have a bag of items with numbers written on them {1, 1, 1, 0, 0}. We take 3 items with 1 written on them, and 1 item with 0 written on it, and get a sum in a total of 3.
It can be proven that 3 is the maximum possible sum.
Constraints:
0 <= numOnes, numZeros, numNegOnes <= 500 <= k <= numOnes + numZeros + numNegOnes
MathGreedy
Hints
Hint 1
It is always optimal to take items with the number 1 written on them as much as possible.
Hint 2
If k > numOnes, after taking all items with the number 1, it is always optimal to take items with the number 0 written on them as much as possible.
Hint 3
If k > numOnes + numZeroes we are forced to take k - numOnes - numZeroes -1s.
Preparing judge…